-11n^2+49n+30=0

Solution for -11n^2+49n+30=0 equation:

-11n^2+49n+30=0

a = -11; b = 49; c = +30;
Δ = b2-4ac
Δ = 492-4·(-11)·30
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-61}{2*-11}=\frac{-110}{-22}
=+5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+61}{2*-11}=\frac{12}{-22}
=-6/11
$